//You are given a large integer represented as an integer array digits, where ea
//ch digits[i] is the ith digit of the integer. The digits are ordered from most s
//ignificant to least significant in left-to-right order. The large integer does n
//ot contain any leading 0's.
//
// Increment the large integer by one and return the resulting array of digits.
//
//
//
// Example 1:
//
//
//Input: digits = [1,2,3]
//Output: [1,2,4]
//Explanation: The array represents the integer 123.
//Incrementing by one gives 123 + 1 = 124.
//Thus, the result should be [1,2,4].
//
//
// Example 2:
//
//
//Input: digits = [4,3,2,1]
//Output: [4,3,2,2]
//Explanation: The array represents the integer 4321.
//Incrementing by one gives 4321 + 1 = 4322.
//Thus, the result should be [4,3,2,2].
//
//
// Example 3:
//
//
//Input: digits = [9]
//Output: [1,0]
//Explanation: The array represents the integer 9.
//Incrementing by one gives 9 + 1 = 10.
//Thus, the result should be [1,0].
//
//
//
// Constraints:
//
//
// 1 <= digits.length <= 100
// 0 <= digits[i] <= 9
// digits does not contain any leading 0's.
//
// Related Topics Array Math
// 👍 4783 👎 4316
//leetcode submit region begin(Prohibit modification and deletion)
class Solution {
public int[] plusOne(int[] digits) {
if (digits == null || digits.length == 0) {
return digits;
}
boolean all9 = true;
for (int digit : digits) {
if (digit != 9) {
all9 = false;
break;
}
}
if (all9) {
int[] result = new int[digits.length + 1];
result[0] = 1;
for (int i = 0; i < digits.length; i++) {
result[i + 1] = 0;
}
return result;
} else {
boolean carry = true;
int i = digits.length - 1;
while (carry) {
digits[i] = digits[i] + 1;
if (digits[i] == 10) {
digits[i] = 0;
} else {
carry = false;
}
i--;
}
return digits;
}
}
}
//leetcode submit region end(Prohibit modification and deletion)