给定一个二叉树的 根节点 root
,想象自己站在它的右侧,按照从顶部到底部的顺序,返回从右侧所能看到的节点值。
示例 1:
输入: [1,2,3,null,5,null,4]
输出: [1,3,4]
示例 2:
输入: [1,null,3]
输出: [1,3]
示例 3:
输入: []
输出: []
提示:
- 二叉树的节点个数的范围是
[0,100]
-100 <= Node.val <= 100
//leetcode submit region begin(Prohibit modification and deletion)
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public List<Integer> rightSideView(TreeNode root) {
List<Integer> result = new ArrayList<>();
Deque<TreeNode> nodeQ = new LinkedList<>();
if (root == null) {
return result;
}
int nodeNum = 1;
nodeQ.add(root);
while (!nodeQ.isEmpty()) {
result.add(nodeQ.peekLast().val);
for (int i = 0; i < nodeNum; i++) {
TreeNode node = nodeQ.poll();
if (node.left != null) {
nodeQ.add(node.left);
}
if (node.right != null) {
nodeQ.add(node.right);
}
}
nodeNum = nodeQ.size();
}
return result;
}
}
//leetcode submit region end(Prohibit modification and deletion)