单词数组 words
的 有效编码 由任意助记字符串 s
和下标数组 indices
组成,且满足:
words.length == indices.length
- 助记字符串
s
以'#'
字符结尾 - 对于每个下标
indices[i]
,s
的一个从indices[i]
开始、到下一个'#'
字符结束(但不包括'#'
)的 子字符串 恰好与words[i]
相等
给定一个单词数组 words
,返回成功对 words
进行编码的最小助记字符串 s
的长度 。
示例 1:
输入:words = ["time", "me", "bell"]
输出:10
解释:一组有效编码为 s = "time#bell#" 和 indices = [0, 2, 5] 。
words[0] = "time" ,s 开始于 indices[0] = 0 到下一个 '#' 结束的子字符串,如加粗部分所示 "time#bell#"
words[1] = "me" ,s 开始于 indices[1] = 2 到下一个 '#' 结束的子字符串,如加粗部分所示 "time#bell#"
words[2] = "bell" ,s 开始于 indices[2] = 5 到下一个 '#' 结束的子字符串,如加粗部分所示 "time#bell#"
示例 2:
输入:words = ["t"]
输出:2
解释:一组有效编码为 s = "t#" 和 indices = [0] 。
提示:
1 <= words.length <= 2000
1 <= words[i].length <= 7
words[i]
仅由小写字母组成
//leetcode submit region begin(Prohibit modification and deletion)
class Solution {
class Trie {
public Trie[] leaves;
public Trie() {
this.leaves = new Trie[26];
}
public void addWord(String word) {
if (word == null) {
return;
}
Trie trie = this;
for (int i = word.length() - 1; i >= 0; i--) {
if (trie.leaves[word.charAt(i) - 'a'] == null) {
trie.leaves[word.charAt(i) - 'a'] = new Trie();
}
trie = trie.leaves[word.charAt(i) - 'a'];
}
}
}
private int result;
public int minimumLengthEncoding(String[] words) {
this.result = 0;
Trie root = new Trie();
for (String word : words) {
root.addWord(word);
}
for (Trie leaf : root.leaves) {
if (leaf != null) {
countPath(leaf, 1);
}
}
return this.result;
}
private void countPath(Trie trie, int curLen) {
boolean allNull = true;
for (Trie leaf : trie.leaves) {
if (leaf != null) {
allNull = false;
countPath(leaf, curLen + 1);
}
}
if (allNull) {
this.result += (curLen + 1);
}
}
}
//leetcode submit region end(Prohibit modification and deletion)