lc-344

发布日期: 2024-07-31

编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 s 的形式给出。

不要给另外的数组分配额外的空间，你必须**原地修改输入数组**、使用 O(1) 的额外空间解决这一问题。

示例 1：

输入：s = ["h","e","l","l","o"]
输出：["o","l","l","e","h"]

示例 2：

输入：s = ["H","a","n","n","a","h"]
输出：["h","a","n","n","a","H"]

提示：

1 <= s.length <= 105
s[i] 都是 ASCII 码表中的可打印字符


//leetcode submit region begin(Prohibit modification and deletion)
class Solution {
    public void reverseString(char[] s) {
        int start = 0;
        int end = s.length - 1;

        while (start < end) {
            char temp = s[start];
            s[start] = s[end];
            s[end] = temp;
            start++;
            end--;
        }
    }
}
//leetcode submit region end(Prohibit modification and deletion)